2020 A$ = "@PROJECTILE MOTION IS SIMILAR TO FREEFALL MOTION, EXCEPT THAT IT INCLUDES A HORIZONTAL COMPONENT IN ADDITION TO A VERTICAL ONE.": GOSUB 10000
2030 VT = VT +1
2040 A$ = "@IF THE MOTION TAKES PLACE IN A FRICTIONLESS ENVIRONMENT, THE HORIZONTAL MOTION IS FOUND USING THE VERY SIMPLE FORMULA:": GOSUB 10000
2050 CENTER = 1
2060 A$ = "S = VT": GOSUB 10000
2070 CENTER = 0
2080 A$ = "@THIS IS, OF COURSE, THE SAME FORMULA AS:": GOSUB 10000
2090 CENTER = 1
2100 A$ = "@DISTANCE = @RATE X @TIME": GOSUB 10000
2110 CENTER = 0
2120 GOSUB 15000
2130 A$ = "@FIRST, LET'S JUST EXAMINE THE VERTICAL COMPONENT OF THE MOTION. @TO DO THIS, IMAGINE THROWING A BALL UP IN THE AIR.": GOSUB 10000
2140 VT = VT +1
2150 A$ = "@TO COMPUTE THE HEIGHT OF THE BALL, WE CAN JUST USE THE FORMULA:": GOSUB 10000
2160 VT = VT +1:CENTER = 1
2170 A$ = "S = 1/2 G T + V T": GOSUB 10000
2180 VT = VT -3
2190 A$ = " 2 ": GOSUB 10000
2200 A$ = " O ": GOSUB 10000
2210 CENTER = 0
2220 VT = VT +1
2230 A$ = "AND TO COMPUTE THE VELOCITY OF THE BALL, WE CAN USE THE FORMULA:": GOSUB 10000
2240 CENTER = 1
2250 A$ = "V = GT + V ": GOSUB 10000
2260 VT = VT -1
2270 A$ = " O": GOSUB 10000
2280 CENTER = 0
2290 GOSUB 15000
2300 A$ = "@NOW LET'S SEE WHAT WILL HAPPEN WHEN WE THROW A BALL UP WITH AN INITIAL VELOCITY OF 30 METERS/SECOND": GOSUB 10000